The figure below shows a horizontal wire of infinite length that carries a const

Question

The figure below shows a horizontal wire of infinite length that carries a constant current of I = 30A flonin to the right. below the vine la distance of x from the wire ) moves a very small par hce of charge / with a speed of v=b xid' m/s directly to the right: (the change moves to the nawet and there is no gravity) Below the horizontal wire is a constant electric field E = (000 N/a f pointing the value of x the motion of down the page : Determine the charged MIROIR par hick is always to the right , parallel to the vire,

Explanation / Answer

magnetic field at a distance x from the wire,

B = mue*I(2*pi*x)

let q is the charge of moving particle.

here magnetic force acts upward and electric force acts downward.

so, For no deflection

magnitude of magnetic force = magnitude of electric force

q*v*B = q*E

v*B = E

B = E/v

mue*I/(2*pi*x) = E/v

==> x = mue*I*v/(2*pi*E)

= 4*pi*10^-7*30*6*10^6/(2*pi*1000)

= 0.036 m or 3.60 cm <<<<<<<------------------Answer

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