(25%) Problem 1: A doubly charged ion is accelerated from rest to a kinetic ener

Question

(25%) Problem 1: A doubly charged ion is accelerated from rest to a kinetic energy of 31 keV by the electric field between two parallel conducting plates separated by 2.15 cm What is the electric field strength between the plates, in volts per meter? E8.00 105 Grade Summa Deductions tan() | | ( | Submissions Attempts remai sinO 78 9HOME cos cotanOasin) acosO atanO acotan)sinh(0 cosh0 tanh) cotanh0 Degrees Radians 0% per attem detailed view 0 ENID VO? BACKSPACE DELI CLEAR Submit Hint I give up! Hints: 10% deduction per hint. Hints remaining: 2 Feedback: 10% deduction per feedback.

Explanation / Answer

Kinetic energy = 31*1.6*10^-19

qV = 31*1.6*10^-19

2*1.6*10^-19*V = 31*1.6*10^-19

V = 15.5 Volts

E = V/d = 15.5 / 0.0215 = 720.9 V/m

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