Safari File Edit View History Bookmarks Window Help 77% Sun Apr 15 10:49 PM E sa

Question

Safari File Edit View History Bookmarks Window Help 77% Sun Apr 15 10:49 PM E saplinglearning.com ?? ANTHRO 152 Google Docs University of California, Merced . PHYS 18-Spring 18-LIU: HW: Tor Physics question | Chegg.com Sapling Learning Jump to.. Ruben Chavez Attempts 4/15/2018 11:59 PM 4 42.9/1004/15/2018 09:06 PM Gradebook Assignment Information Print Calculator Periodic Table Question 18 of 21 Available From: Not Set Due Date: Points Possible: 100 Grade Category: Graded Description Policies: Map 4/15/2018 11:59 PM Sapling Learning The Atwood machine consists of two masses hanging from the ends of a rope that passes over a pulley. The pulley can be approximated by a uniform disk with mass mp-6.33 kg and radius r 0.250 m. The hanging masses are m 21.9 kg and 11.5 kg. 10 Calculate the magnitude of the masses' acceleration a, and the tension in the left and right ends of the rope. 12 13 14 You can check your answers. You can view solutions when you com give up on any question. You can keep trying to answer each qu until you get it right or give up. You lose 5% of the points available to answer in your question for each incor attempt at that answer 21.9 kg Number 11.5 kg eTextbook 16 17 18 19 20 21 Number Help With This Topic O Web Help & Videos O Technical Support and Bug Rep Previous Give Up &View; Solution Check NxtExit Hint

Explanation / Answer

here,

m1 = 21.9 kg

m2 = 11.5 kg

mp = 6.33 kg

rp = 0.25 m

a)

the accelration of the system , a = net force /effective mass

a = ( m1 - m2) * g /( m1 + m2 + 0.5 * mp * rp^2 /rp^2)

a = ( 21.9 - 11.5) * 9.81 /(21.9 + 11.5 + 0.5 * 6.33) m/s^2

a = 2.79 m/s^2

b)

for m1

m1 * g - T1 = m1 * a

T1 = 21.9 * ( 9.81 - 2.79) N

T1 = 153.7 N

the tension in the left string is 153.7 N

c)

for m2

T2 - m2 * g = m2 * a

T2 = 11.5 * ( 9.81 + 2.79) N

T2 = 144.9 N

the tension in the right side string is 144.9 N

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.