You\'re an investigator for the National Transportation Safety Board, examining

Question

You're an investigator for the National Transportation Safety Board, examining a subway accident in which a train going at 88 collided with a slower train traveling in the same direction at 25 . Your job is to determine the relative speed of the collision, to help establish new crash standards. The faster train's "black box" shows that it began negatively accelerating at 1.9 when it was 50 from the slower train, while the slower train continued at constant speed.

I got that the relative speed of the collision was 47km/h but my teacher said I did it wrong that i should have used the equation: change of x= Vinitial + 1/2at^2 where change of x equals distance + 50 and that i will end up using the quadratic equation and thats all he gave me to work with and im totally lost.

Explanation / Answer

similar question hope this will help You're an investigator for the National Transportation Safety Board, examining a subway accident in which a train going at 22.77m/s collided with a slower train traveling in the same direction at 5.83m/s . Your job is to determine the relative speed of the collision, to help establish new crash standards. The faster train's "black box" shows that it began negatively accelerating at 2.2 m/s^2 when it was 40m from the slower train, while the slower train continued at constant spee Vri = 22.77 - 5.83 = 16.94 m/s D = (Vri² - Vc²)/(2*a) ? Vc = v[Vri² - 2*D*a] = 10.53 m/s Source(s): Eqs of constant acceleration with time eliminated

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