A duck has a mass of 2.4 kg. As the duck paddles, a force of 0.14 N acts on it i

Question

A duck has a mass of 2.4 kg. As the duck paddles, a force of 0.14 N acts on it in a direction due east. In addition, the current of the water exerts a force of 0.15 N in a direction of 50° south of east. When these forces begin to act, the velocity of the duck is 0.13 m/s in a direction due east. Find the magnitude and direction (relative to due east) of the displacement that the duck undergoes in 3.7 s while the forces are acting. magnitude in meters? and,
direction is how many degrees south of east?

Explanation / Answer

The component of forces are S Fx = 0.14 N + (0.10Cos 51)= S Fy = - 0.1 Sin 51 = According to newtons law the accelerations ax = SFx / m ay= SFy / m The displacement in x and y directions x = Vox t + (1/2) axt2 Vox = 0.11 m/s t = 2.2 sec y = (1/2) ayt2 The magnitude ofthe displacement D = v [x2 +y2 ] The direction is ? = tan-1[ y / x] do the calculations.

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