Vab Five capacitors are connected across a potential difference as shown in Fig.
ID: 2047712 • Letter: V
Question
Vab Five capacitors are connected across a potential difference as shown in Fig. Because of the dielectrics used, each capacitor will break down if the potential across it is V=15 V. What should be the value of Vab (with one decimal place) if you reach the break down voltage one of the capacitor.a--------------15uF---45uF-------
Vab is between a and a 5.0uF
b------ --------10uF----25uF
Explanation / Answer
From the above equation it is evident that if capacitance is low, Voltage across it will be high. Among all 5 capacitors 5µF is the smallest capacitor. Assuming Voltage across it is 30V, ---> V5 = 30V Voltage across 15µF capacitor is V15 = 30*5/15 = 10V (Here C1V1 = C2V2) Voltage across 45µF capacitor is V45 = 30*5/45 = 10/3 = 3.33V Voltage across 25µF capacitor is V25 = 30*5/25 = 6V Voltage across 10µF capacitor is V10 = 30*5/10 = 15V Largest Voltage Vab = 10+3.333+30+6+15 = 64.333V ˜ 64V
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