You were driving a car with velocity ‹ 28, 0, 14 › m/s. You quickly turned and b

Question

You were driving a car with velocity ‹ 28, 0, 14 › m/s. You quickly turned and braked, and your velocity became ‹ 21, 0, 18 › m/s. The mass of the car was 1100 kg.

(a) What was the (vector) change in momentum ? during this maneuver? Pay attention to signs.

? = kg · m/s

(b) What was the (vector) impulse applied to the car by the ground?

(vector) impulse: N · s

(c) If the maneuver took 7 seconds, what was the the average (vector) force exerted on the car? (The net force is due to the ground and the Earth; the y components of these forces cancel.)

net = N

Explanation / Answer

Please ask if you have any doubt.I will help you.

a) vector change in momentum = final momentum - initial momentum

P = m(21,0,18) - m(28,0,14) = m(-7,0,4) = (-7700,0,4400) kgm/s.

b) Impulse is change of momentum or large force in small duration of time.

vector impulse by ground = (-7700,0,4400) kgm/s.

c) The average vector force = (-7700,0,4400)/7 N = (-1100,0,4400/7) N

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