<p><span>A gymnast of mass </span><span>51.0</span><span> </span><img
ID: 2048824 • Letter: #
Question
<p><span>A gymnast of mass </span><span>51.0</span><span> </span><img src="http://session.masteringphysics.com/render?units=%7B%5Crm+kg%7D" alt="{ m kg}" align="middle" /><span> hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch. Use the value </span><img src="http://session.masteringphysics.com/render?tex=9.81+%7B%5Crm+m%2Fs%5E2%7D" alt="9.81 { m m/s^2}" align="middle" /><span> for the acceleration of gravity.</span></p><p> </p>
<p><span><span>Calculate the tension </span><img title="T" src="http://session.masteringphysics.com/render?var=T" alt="T" align="middle" /><span> in the rope if the gymnast hangs motionless on the rope.</span></span></p>
<p><span><span><span>Calculate the tension </span><img title="T" src="http://session.masteringphysics.com/render?var=T" alt="T" align="middle" /><span> in the rope if the gymnast climbs the rope at a constant rate.</span></span></span></p>
<p><span><span><span><span>Calculate the tension </span><img title="T" src="http://session.masteringphysics.com/render?var=T" alt="T" align="middle" /><span> in the rope if the gymnast slides down the rope with a downward acceleration of magnitude </span><span>0.700</span><span> </span><img src="http://session.masteringphysics.com/render?units=%7B%5Crm+m%2Fs%5E2%7D" alt="{ m m/s^2}" align="middle" /><span>.</span><br /></span></span></span></p>
Explanation / Answer
Answer:
(a)When the gymnast hangs motionless, total force on him =0
mg-T =0
T = 51*9.8 = 499.8 N
(b)When he moves with a constant velocity, net acceleration = 0
So, net force =0
T = 499.8 N
(c)When he moves with 0.7 m/s^2 downwards,
mg-T = ma
T = 51(9.8-0.7) = 464.1 N
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