In the figure here, a red car and a green car move toward each other in adjacent

Question

In the figure here, a red car and a green car move toward each other in adjacent lanes and parallel to an x axis. At time t = 0, the red car is at xnu = 0 and the green car is at x sigma = 214 m. If the red car has a constant velocity of 26.0 km/h, the cars pass each other at x = 44.1 m. On the other hand, if the red car has a constant velocity of 52.0 km/h, they pass each other at x = 76.1 m. What are the initial velocity (in km/h) and the (constant) acceleration (in m/s2) of the green car? Include the signs. Number Unit Number Unit m/s^2

Explanation / Answer

26 km/hr = 7.22 m/s 52 km/hr = 14.44 m/s Let the initial velocity be u and acceleration be a for green car In the first case, time taken to cross = 44.1/7.22 = 6.11 seconds (216-44.1) = u*6.11 + 1/2 * a * 6.11^2 6.11u + 18.64a = 171.9 For the second case, time = 76.1/14.44 = 5.27 seconds (216-76.1) = u*5.27 + 1/2*a*5.27^2 5.27u + 13.88a = 139.9 solving the equations, we get u = 16.52 m/s a = 3.81 m/s^2

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