Three forces area acting on an object in such a way that the net force on the ob

Question

Three forces area acting on an object in such a way that the net force on the object is zero. Two of the forces are shown in the diagram. Find the magnitude and direction of the third force.

If A= 20N, 130 degrees and B= 40N, -35 degrees. I can add them and come up with    A+B = 60N   net xCos =    -43.49 and net ySin = -35.73. In previous problems I have been able to add the up and get the correct answers but not that I have to find angle C to make the total net = 0 im stuck to the point where I'm hurting my existing understanding.   Please let me know if this qualifies as two questions and I will break it up.

Explanation / Answer

Let X= A +B = 20angle(130) + 40 angle(-35) Xx = 20cos(130) + 40 cos(-35) = 19.91 N Xy = 20sin(130) + 40 sin(-35) = -7.622 N Third force C = -X Cx = -19.91 N Cy = 7.622 N AngleC = 180-atan(7.622/19.91) = 159.05 deg C = 21.319 N angle(159.05)

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