http://www.csupomona.edu/~pbsiegel/physprobs/p131b11/ProblemsApp.html please fol

Question

http://www.csupomona.edu/~pbsiegel/physprobs/p131b11/ProblemsApp.html

please follow this link

Problem B11: A ball is thrown from one cliff towards another cliff. The speed of the ball is n1 m/s. The sin of the angle with respect to the horizon is sin&theta = 3/5. Unfortunately, the ball is not thrown with enough speed to reach the top of the other cliff, and lands below the level a distance of n3 meters. The two cliffs are a distance of n2 meters apart. Take the acceleration of gravity g = 10 m/s2. What is n3?

n1=1, n2=4

Explanation / Answer

Horizontal component of velocity = n1 costheta = 1*4/5 = 4/5 m/s Time taken to cross = n2/4/5 = 5 seconds Height traveled in 5 sec = 3/5*5 - 1/2*(10*5^2) = 3-125 = 122 n3 = 122m

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.