Find the total electric-field energy U stored in the capacitor Two oppositely ch

Question

Find the total electric-field energy U stored in the capacitor

Two oppositely charged but otherwise identical conducting plates of area 2.50 square centimeters are separated by a dielectric 1.80 millimeters thick, with a dielectric constant of . The resultant electric field in the dielectric is volts per meter.

a.) Compute the magnitude of the charge per unit area on the conducting plate.
answer: =3.82×10-5

b.)Compute the magnitude of the charge per unit area on the surfaces of the
dielectric.
answer: 2.76×10-5

c.) Find the total electric-field energy stored in the capacitor??????????????????

Explanation / Answer

A) =3.82×10-5 B) =2.76×10-5 Note that the charges on the dielectric will be polarized tocounteract the charges (and electric field) created by thecapacitor. For example, near the positive surface of the capacitorthe dielectric will have a negative charge. However, this does notmean that the charge on the capacitor plates changes, only that thedielectric has an induced charge on each of its surfaces that willoppose the effects of the charges on the plates. C) For C use the electric field density with a dielectric(u) u=1/2*K*e0*E2 u=22.9 J/m3 and u=U/(Ad) so,U=u*A*d=1.03*10-5 J

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.