In a lab, a student measures the unstretched length of a spring as 11.2 cm. When

Question

In a lab, a student measures the unstretched length
of a spring as 11.2 cm. When a 100.0-g mass is hung from
the spring, its length is 20.7 cm. The mass-spring system is
set into oscillatory motion, and the student observes that the
amplitude of the oscillation decreases by about a factor of 2
after five complete cycles.

a) Calculate the period of oscillation for this system,
assuming no damping. (solved, T= 0.602 s)

b) If the student can measure the period to the nearest 0.05 s,
will she be able to detect the difference between the period
with no damping and the period with damping?

Explanation / Answer

2. Relevant equations F = -k?x T = 2?/v(k/m) ?x = x2 - x1 3. The attempt at a solution a. ?x = x2 - x1 = 20.7 - 11.2 = 9.5 cm = 0.095 m F = -k?x -k = F/?x = mg/?x = .98/.095 = 10.31 N/m T = 2? / v(k/m) = .62 s b. Not sure how to even start with this one.... 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution

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