The electric field strength just outside the outer surface of a 1.0 cm thick hol

Question

The electric field strength just outside the outer surface of a 1.0 cm thick hollow conducting sphere of outer radius 18.0 cm is E=720 N/C directed outward. An unknown charge Q is then introduced into the center of the sphere (not touching or transferring any charge to the sphere itself) and it is noted that the electric field is still directed outward but has decreased to 280 N/C.

How much charge is on the surface of the sphere after Q is introduced and what is the value of the introduced charge Q ?

Explanation / Answer

r = 0.19m initial charge = 720 = kq/r^2 q = 2.888*10^-9C now we know 720 - 280 = kq/r^2 q = -1.76*10^-9C total charge = 1.128 *10^-9 C charge introduced = -1.76*10^-9C

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.