V slab of insulating material (not metal!) with infinite area (infinite y-z plan
ID: 2056215 • Letter: V
Question
V slab of insulating material (not metal!) with infinite area (infinite y-z plane) has a uniform positive charge density rho. An edge view of the slab is shown in the figure on the right. You will find the electric field E inside the slab at distance x from the center (O). Imagine a rectangular solid as a Gaussian surface of area A and thickness t (in x direction) inside the slab. Assume the left surface of the Gaussian surface is at x=0 (on the y-z plane). It is clear that electric field E. if any, is perpendicular to the y-axis and in the positive or negative X direction. Find the net flux that penetrates the Gaussian surface in terms of E at X=t (denote it by E(t)) and A. Note E(0) is not the same as E(t). Find the amount of charge inside the Gaussian surface in terms of A, t, and rho. Show that E(t) = rho t/c0Explanation / Answer
(a)Electric field at the center of the slab is 0 because the charge is uniformly distributed throughout the slab. So E(0) = 0.
Electric field at the surface at x=t is E(t) . So, the total flux leaving the gaussian surface with area A is E(0)*A + E(t)*A = E(t)*A
(b) Amount of charge enclosed = volume * charge density = A*t*
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.