the plot of this groph (for liver catolase added to at 35\'C celcius) would chan
ID: 205683 • Letter: T
Question
the plot of this groph (for liver catolase added to at 35'C celcius) would change if a higher concentration of enzyme was used. 3 pt) peroxide, in a tral pH rd Describe how the plot of the above graph would change if the reaction was (1 pt) b. r'ot of the above 3nrn would dec . ease a stead Give one reason (in the graph above) that the amount of oxygen produced starts to plateau over time. Hint- the answer is NOT that the enzyme denatured. (1 pt) c. 12.) In the cow liver juice experiment, what was the purpose of using the liver? (0.5 pts)Explanation / Answer
11a. The graph would increase with more oxygen being released. For liver sample, the plot will plateau faster, as more active sites are available for the enzymatic reaction. However, the substrate added is constant. Hence, oxygen will be released faster will plateau out much faster as enzymatic reaction is faster. For the potato sample, the increased enzyme levels, will result in the curve increasing and being similar (less though in area) to the curve for liver sample at ambient conditions (neutral pH and 350C). This results in more active sites being available for catalysis.
b. At higher temperature of 700C, the plot will decrease dramatically (will nearly merge with X axis) as temperature denatures the enzyme. Liver catalase has an optimum temperature of 370. Denaturation will cause loss of enzyme activity, which will result in no oxygen release with time.
c. The catalase will break down the hydrogen peroxide to oxygen. However, over time the active site of the enzymes will be completely filled with the substrate. Hence, there will be no increase in number of active sites available for substrate binding as time progresses. This will cause plateau in the graph.
12. The cow’s liver contains catalase enzyme, which is extracted in the juice. This liver will act as source of catalase enzyme in the experiment. Catalase breaks down hydrogen peroxide to oxygen.
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