A 10 kg crate is at rest on a horizontal table (s =0.6, k =0.3). Then various am
ID: 2057116 • Letter: A
Question
A 10 kg crate is at rest on a horizontal table (s =0.6, k =0.3). Then various amounts of horizontal pushing force are applied to it.a.) The largest pushing force that can be applied before the crate starts moving is of size:
N
b.)-d.) If the pushing force were instead the two amounts shown below, please fill in the rest of the values on the chart below:
horizontal pushing force:
friction force: (size only)
(indicate static or kinetic):
net force on crate:
(size only)
acceleration of crate:
(size only)
11 N N, N m/s2
100 N N, N m/s2
Explanation / Answer
Fn=normal force=10*9.81=98.1N
F needed to puch the crate=98.1*.6=58.86N
11N)
58.86N is the miniumum force needed to puch the crate
Friction force=11N due to static friction
Net force=0
acceleration=0
100N)
100N force is greater than 58.86 needed to overcome static friction so the crate is moving
Force due to friction=Fn*.3=29.43 N
Net force=100-29.43=70.57N
acceleration=F/m=70.57/10=7.057m/s2
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.