The trick to find the time constant here is to consider only the charging proces

Question

The trick to find the time constant here is to consider only the charging process. Let t = 0 be the time when V = 0. In other words, consider only the charging part of the curve:

Vertical scale : 5 V/major division
Horizontal scale : 3 ms/major division




We can now use the same procedure as before to determine ! Since the curve is quite flat at the end of the graph, you may assume that that is V

Find the time constant (in ms –NOTE UNITS!) for the display. (This question allows for 10% error since it is based on reading a graph).

Explanation / Answer

time constant = 3*5 =15ms

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