As a member of a team of storm physicists. you are attempting to replicate light

Question

As a member of a team of storm physicists. you are attempting to replicate lighting by Charging two long cables stretched over a canyon, as shown. One cable will attain a highly positive (and uniform) charge density of +A and the other will attain the same amount of charge density, but opposite in sign (i.e.. -A). Since the appearance of lighting directly depends on the electric field strength created by charge separation, it is important to derive an expression (or electric fold strength at an points between the two cables (albeit near the midpoint of the wires). The cables are sufficiently long as to be considered (for ai practical purposes) infinitely long. Calculate the magnitude of the electric field strength between the two cables as a function of A (the in car charge density) and r (the distance from the positively charged cable). Use epsilon0 as the permitivity of free space and assume the wires are separated by a distance D. If the charge density separation between the two cables is A = 50 5 mu C and the distance between the two cables is D = 50.5 m. calculate the electric field midway between the two cables.

Explanation / Answer

sorry got confused. the final answer is . a) 2*?/(2*p*e*d) = 2*?/(p*e*D) b) here given d = D/2 and ? = 50.5 µC => E = 50.5*10^-6/(p*8.85*10^-12*25.25) = 71934.437 N/C (towards the negative line of charge)

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