When a resistor is connected across the terminals of an ac generator (122 V) tha

Question

When a resistor is connected across the terminals of an ac generator (122 V) that has a fixed frequency, there is a current of 0.485 A in the resistor. When an inductor is connected across the terminals of this same generator, there is a current of 0.416 A in the inductor. When both the resistor and the inductor are connected in series between the terminals of this generator, calculate the following.
(a) the impedance of the series combination
O

(b) the phase angle between the current and the voltage of the generator
°

Explanation / Answer

a)impedance = sqrt((122/.485)^2 + (122/.416)^2) = 386.4 ohm b) phase angle = tan-inverse ((122/0.416)/(122/0.485)) = 49.4 degrees

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