8). A conductive bar that is 0.500 meters long is pulled to the right with a con

Question

8). A conductive bar that is 0.500 meters long is pulled to the right with a constant speed. The upper and lower edges of the bar are in contact with conductive material such that a rectangular loop is formed. There is a uniform magnetic field of 0.750 T directed into the page. (perpendicular to the plane of the loop).

A). If the total resistance of the loop is is constant at 250 Ohms , what speed must the bar have to induce a current of 0.125 Amps in the loop?

B). With what force must the bar be pulled to the right? (considering part a)

Explanation / Answer

This is an outcome of Faraday's law also known as motional emf

When a rod is moving in a magnetic field it generates a potential difference of
e = vbl
across it ends.

now i(current) = vbl/R

Given in qstn
b= 0.75 T
l = 0.5m
r = 250 ohm
i = 0.125 amps

putting these in above equation we get v = 83.34 m/s

b)As soon as a current is introduced in the bar it experiences a force
= ibl

So we need to apply this exact force to keep the rod moving.

Solving we get

ibl = 0.0468 N

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