Suppose you take a 2.0×102 (ohm) resistor and a 6.0 Micro F capacitor and make a

Question

Suppose you take a 2.0×102 (ohm) resistor and a 6.0 Micro F capacitor and make a series circuit with a voltage source that has voltage amplitude 30 V and an angular frequency of 2.5×102 rad/s.

Z= 696 Ohms

What is the current amplitude?

Calculate the voltage amplitudes across the resistor and the capacitor.

What is the phase angle of the source voltage with respect to the current?


Does the source voltage lag or lead the current?
A. The source voltage lags the current.
B. The source voltage leads the current.
(Please explain why)

Explanation / Answer

I don't know what happened to my first answer,=R*C=200*6E-6=1.2 mseconds

i(t)=V/R*e-t/==>Vc(t)=30*(1-e-t/)==>VR=i(t)*R

tan(200/696)-116o==>During my apprentice years I was taught ELI-ICE

means Eli the Iceman, in the capacitor current leads the voltage or

voltage lags the current A is the answer

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