A luggage handler pulls a suitcase of mass 30.8 KG up a ramp inclined at an angl

Question

A luggage handler pulls a suitcase of mass 30.8 KG up a ramp inclined at an angle 18.3 degrees above the horizontal by a force of magnitude 290 N that acts parallel to the ramp. The coefficient of kinetic friction between the ramp and the incline is 0.267. The suitcase travels a distance 4.40 m along the ramp.


Calculate the work done on the suitcase by the force .


Calculate the work done on the suitcase by the gravitational force.


Calculate the work done on the suitcase by the normal force.


Calculate the work done on the suitcase by the friction force.


Calculate the total work done on the suitcase.


If the speed of the suitcase is zero at the bottom of the ramp, what is its speed after it has traveled 4.40 along the ramp?

Explanation / Answer

work done = f x d

= 290 x 4.4 = 1276 J

work done by gravity = mgx4.4sin 18.3

= 30.8x9.81x4.4x0.313 = 417.44 J

work done by normal = 0

work done on the suitcase by the friction force = mgcos 18.3 x 4.4 = 337.011 J

total work done on the suitcase = (f - mgcos 18.3) x d

= ( 290 -0.267x30.8x9.81x0.949) x 4.4 = 939.14 J

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