Three uniform meter sticks, each of mass $m$, are placed on the floor as follows

Question

Three uniform meter sticks, each of mass $m$, are placed on the floor as follows: stick 1 lies along the $y$ axis from $y$ = 0.210 m to $y$ = 1.21 m, stick 2 lies along the $x$ axis from $x$ = 0.190 m to $x$ = 1.19 m, stick 3 lies along the $x$ axis from $x$ = 1.41 m to $x$ = 2.41 m. Calculate the location of the center of mass of the meter sticks. Enter the $x$ value first and then the $y$ value. Calculate the location of the center of mass if the mass of the meter sticks were doubled. Enter the $x$ value first and then the $y$ value.

Explanation / Answer

center of mass of stick one is at x1 = .21+.5 = .71 for stick 2 x2 = .19 + .5 = .69 for stick 3 x3 =1.41 + .5 = 1.91 center of mass of the meter sticks = (m*.71+m*.69+m*1.91)/3m = 1.1 m along the axis

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