Object O1 is 15.8 cm to the left of a converging lens with a 10.7-cm focal lengt

Question

Object O1 is 15.8 cm to the left of a converging lens with a 10.7-cm focal length. A second lens is positioned 10.0 cm to the right of the first lens and is observed to form a virtual image at the position of the original object O1.
(a) What is the focal length of the second lens?
=_______ cm

(b) What is the overall magnification of this system?
=__________

(c) What is the nature (i.e., real or virtual, upright or inverted) of the final image? Pick one.....
real and inverted
virtual and upright
real and upright
virtual and inverted

Explanation / Answer

1/f = 1/v -1/u 1/10.7 = 1/v1 + 1/15.8 v1 = 33.149 cm now u2 = 33.149 - 10 = 23.149 v2 = 10 +15.8 = 25.8 cm 1/f = 1/25.8 + 1/23.149 focal length of the second lens , f = 12.2 cm b) m1 = -33.149 / 15.8 = -2.098 m2 = -25.8 / 23.149 = -1.1145 overall magnification of this system = m = m1 x m2 = 2.338 c) virtual and upright

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