A11. A child of mass 50.0 kg stands 2.00 m from the center of a horizontal circu

Question

A11. A child of mass 50.0 kg stands 2.00 m from the center of a horizontal circular disc of radius 4.00 m and mass 200 kg. The disc is mounted on a frictionless, vertical axis. Initially both the child and the disc are at rest. (Hint: so what is their combined initial angular momentum?) The child then begins to run in a counter clockwise direction. Shortly after the child starts running, it is observed that the disc attains a steady angular velocity of ? = -0.125rad/s in a clockwise sense. The moment of inertia of the flat disc is given by: I = 1/2 mR^2

Calculate the angular momentum of the disc (NOT the child) about the central vertical axis when the child has reached its steady (constant) tangential speed. Also calculate the steady tangential speed at which the child is running

Explanation / Answer

Part A)

L = I

L = (.5)(200)(4)2(-.125)

L = -200 kgm2/s2

Part B)

v = r

v = (.125)(2)

v = .25 m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.