In a tape recorder, the magnetic tape moves at a constant linear speed of 3.51 c

Question

In a tape recorder, the magnetic tape moves at a constant linear speed of 3.51 cm/s. To maintain this constant linear speed, the angular speed of the driving spool (the take-up spool) has to change accordingly.
The angular speed of the take-up spool when it is empty, with radius r1 = 0.80 cm?
4.388 1/s
The angular speed when the spool is full, with radius r2 = 2.20 cm?
1.595 1/s
If the total length of the tape is 89.5 m, what is the average angular acceleration of the take-up spool while the tape is being played?
I have tried out this -0.00205 rad/s^2 but it is wrong.
I want a step by step answer.

Explanation / Answer

t = (total length of the tape) / (linear speed of tape)

    = (89.5) / (0.0351)

    = 2549.858 s

-------------------------------------------------------

= /t

   = (1.595 - 4.388) / (2549.858)

   = -0.001095 rad/s2

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