A 0.80-m-long organ pipe that is open at both ends resonates in the fundamental

Question

A 0.80-m-long organ pipe that is open at both ends resonates in the fundamental when a tuning fork of unknown frequency vibrates near one end of the pipe. Given the same value for the speed of sound from part a., (Part a was If the density and adiabatic compressibility of the surrounding air are known to have the values ?= 1.3 kg/m^3 and B= 1.50 x 10^5 N/m^2 respectively, find the speed of sound using vSOUND = vB/?. Round final answer to the nearest whole number ) what would be the fundamental frequency of a 0.80-m-long pipe that is open at one end and closed at the other?

Explanation / Answer

For a pipe closed at one end, the wavelength is 4 times the pipe length

v = f

340 = (f)(4)(.80)

f = 106.25 Hz

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