1. In a standing wave on a string, the spacing between nodes is x. If the tensio
ID: 2066015 • Letter: 1
Question
1.
In a standing wave on a string, the spacing between nodes is x. If the tension in the string is doubled but the frequency of the standing wave is fixed, then the spacing between the nodes will change to
a) 2x
b) x/2
c) (2)x
d) x/2
2.
In the arrangement shown in the figure below a mass m can be hung from a string (with a linear mass density of 0.002 kg/m) that passes over an ideal pulley. The string with a length of L = 2 m is connected to a vibrator of constant frequency. Find the mass m of the object when standing waves with a fundamental frequency of 120 Hz are observed in the string.
1. In a standing wave on a string, the spacing between nodes is x. If the tension in the string is doubled but the frequency of the standing wave is fixed, then the spacing between the nodes will change to 2. In the arrangement shown in the figure below a mass m can be hung from a string (with a linear mass density of 0.002 kg/m) that passes over an ideal pulley. The string with a length of L = 2 m is connected to a vibrator of constant frequency. Find the mass m of the object when standing waves with a fundamental frequency of 120 Hz are observed in the string.Explanation / Answer
a)c
b) fundamental or first mode has frequency f1 = v/1 = v/2L,
v=2Lf1=2*2*120=480m/s
v=(T/)
T=>v^2*
480*480*.002=460
T=mg
460/10=m=46
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