During a hurricane the wind speed increases dramatically outside the house while

Question

During a hurricane the wind speed increases dramatically outside the house while inside the air does not move, this creates a pressure difference that puts a lot of stress on the windows. Assume that the air pressure inside of a sealed house is P atm = 1 Atm = 1 X 10^5 Pa and the winds of the hurricane oustide the house are 60 m/s, what is the net force exerted on a window with an area of 1.5 m^2 that is on the side of the house? (ignore the change in pressure due to the height of the window) density of air = 1.3 kg/m^3

Explanation / Answer

By bernoulli's eqn,
p1-p2= 0.5(v22-v12)

p= 0.5*1.3*(602-0)=2340N/m2

Force= p*A= 2340*1.5=3510N

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