A charged particle is injected at 261 m/s into a 0.0719-T uniform magnetic magne

Question

A charged particle is injected at 261 m/s into a 0.0719-T uniform magnetic magnetic field perpendicularly to the field. The diameter of its orbit is measured and found to be 0.0379 m. What is the charge-to-mass ratio of this particle?

= _____________ C/kg

A proton moves through a magnetic field at 31.5% of the speed of light. At a location where the field has a magnitude of 0.00695 T and the proton's velocity makes an angle of 129° with the field, what is the magnitude of the magnetic force acting on the proton?

= ____________ N

Explanation / Answer

1) mv2/r = qvb

==> q/m= v/rB = 1.915 x 107 C/KG( by putting the values)

2) force on proton:

F = qvB sin

hence, F = 1.6 x 10-19 x 31.5 x 3 x 106 x 6.95 x 10-3 x sin (129)

hence, F = 8.1 x 10-14 N

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