A tourist being chased by an angry bear is running in a straight line toward hs

Question

A tourist being chased by an angry bear is running in a straight line toward hs car at a speed of 4.0 m/s. The car is a distance d away. The bear is 26 m behind the tourist and running at 6.0 m/s.   The tourist reaches the car safely. Need to know: maximum possible value for d.

Please give me a written explanation of the steps. I already know:

Avg speed = displacement/elapsed time

26m/2s = 13m/s  

4m/s x 13 s = 52 meters The max possible value for d is 52 meters.

I don't understand how to do the steps in between all that. How do i set up the problems from the beginning?

Explanation / Answer

for maximum d :he reaches the car just before bear reaches him let in time t he reaches his car by traveling a distance of d m in this same time bear has to travel 26+d m d = 4*t ---->for the tourist 26+d = 6*t --->for the bear 26 = 6t-4t = 2t t = 13 s d = 4*13 = 52 m

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