After being accelerated through a potential difference of 5.0 kV, a singly, nega

Question

After being accelerated through a potential difference of 5.0 kV, a singly, negatively charged carbon-14 ion (atomic mass 14 u; m14mp) moves in the positive x-direction into a region of uniform magnetic field B. We would like the carbon ion to emerge from the region of magnetic field traveling in the negative x-direction at a distance d=0.20 m from the incident path as shown below.

(a) Determine the direction of the magnetic field, and sketch the path of the carbon ion in the region of magnetic field.

(b) What is the speed of the carbon ion after it is accelerated through the 5.0-kV potential difference?

(c) What is the strength of the magnetic field needed?

(d) How much time does the carbon ion spend traveling in theregion of magnetic field?

Explanation / Answer

a) magnetic field pointing out of the page(using left hand rule for negative charge)

b) Energy given to the carbon atom is e* 5.0-kV where is the charge on an electron
Energy = 1/2 mv^2 then solve for v

c) mv^2/r = v X B then solve for B using the given r

d) pi(r)/v

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