In the figure 30-56, a metal rod is forced to move with constant velocity along

Question

In the figure 30-56, a metal rod is forced to move with constant velocity along two parallel metal rails, connected with a strip of metal at one end. A magnetic field of magnitude B = 0.397 T points out of the page. (a) If the rails are separated by 20.8 cm and the speed of the rod is 58.9 cm/s, what is the magnitude of the emf generated in volts? (b) If the rod has a resistance of 21.5 ? and the rails and connector have negligible resistance, what is the current in amperes in the rod? (c) At what rate is energy being transferred to thermal energy?

Explanation / Answer

(a) emf = BLv = 0.397 * 0.208 * 0.589 = 0.04864 Volts

(b) current = emf / resistance = 0.04864 / 21.5 = 0.002262 Amps

(c) rate of energy = current^2 * resistance = 0.002262^2 * 21.5 = 0.000110 Watts

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