genetics Scenario 1: Scenario 2: a w Aa Gen. o Gen. O Genotype #s Genotype #s Ge
ID: 207202 • Letter: G
Question
genetics
Scenario 1: Scenario 2: a w Aa Gen. o Gen. O Genotype #s Genotype #s Genotype Freq's Allele Freas Genotype Freq's a : Total = 14 Total : Gen. 1 Genotype #s Gen. 1 Genotype #5 Genotype Freq's Allele Freqs Genotype Freqs Total 14 Total Gen. 2 Genotype #s Genotype #s AA-6 Aa- aa = 2 Total 4 Genotype Freqs Allele Freq's Genotype Freq. Total Gen. 3 Genotype #s Gen. 3 Genotype#s Genotype Freqs Allele Freqs Genotype Freq Aa= Aa = aa 2 Total Y Gen. 4 Genotype #s Aaslo Total = (4 Total= 14 Gen. 4 Genotype #s Genotype Freq's Allele Freq.s Genotype Free Aas aa = Total 14 1.0 0.5 0.5Explanation / Answer
SCENARIO - 1
GEN 0:
Genotype #s
AA = 6
Aa = 6
aa = 2
Total = 14
Genotype Frequencies
AA = 6/14 = 0.4286
Aa = 6/14 = 0.4286
aa = 2/14 = 0.1428
Allele Frequencies
p = Frequency of A = [(2 * 6) + 6] / 28 = 18/28 = 0.643
q = frequency of a = [(2*2)+6] / 28 = 10/28 = 0.357
GEN 1:
Genotype #s
AA = 5
Aa = 8
aa = 1
Total = 14
Genotype Frequencies
AA = 5/14 = 0.35714
Aa = 8/14 = 0.57143
aa = 1/14 = 0.07143
Allele Frequencies
p = Frequency of A = [(2 * 5) + 8] / 28 = 18/28 = 0.643
q = frequency of a = [(2*1)+ 8] / 28 = 10/28 = 0.357
GEN 2:
Genotype #s
AA = 6
Aa = 6
aa = 2
Total = 14
Genotype Frequencies
AA = 6/14 = 0.4286
Aa = 6/14 = 0.4286
aa = 2/14 = 0.1428
Allele Frequencies
p = Frequency of A = [(2 * 6) + 6] / 28 = 18/28 = 0.643
q = frequency of a = [(2*2)+6] / 28 = 10/28 = 0.357
GEN 3:
Genotype #s
AA = 6
Aa = 6
aa = 2
Total = 14
Genotype Frequencies
AA = 6/14 = 0.4286
Aa = 6/14 = 0.4286
aa = 2/14 = 0.1428
Allele Frequencies
p = Frequency of A = [(2 * 6) + 6] / 28 = 18/28 = 0.643
q = frequency of a = [(2*2)+6] / 28 = 10/28 = 0.357
GEN 4:
Genotype #s
AA = 4
Aa = 10
aa = 0
Total = 14
Genotype Frequencies
AA = 4/14 = 0.2857
Aa = 10/14 = 0.7143
aa = 0/14 = 0
Allele Frequencies
p = Frequency of A = [(2 *4 ) + 0] / 28 = 8/28 = 0.2857
q = frequency of a = [(2*10) + 0] / 28 = 20/28 = 0.7143
SCENARIO - 2
GEN 0:
Genotype #s
AA = 4
Aa = 10
aa = 0
Total = 14
Genotype Frequencies
AA = 4/14 = 0.2857
Aa = 10/14 = 0.7143
aa = 0/14 = 0
Allele Frequencies
p = Frequency of A = [(2 *4 ) + 0] / 28 = 8/28 = 0.2857
q = frequency of a = [(2*10) + 0] / 28 = 20/28 = 0.7143
GEN 1:
Genotype #s
AA = 7
Aa = 4
aa = 3
Total = 14
Genotype Frequencies
AA = 7/14 = 0.5
Aa = 4/14 = 0.2857
aa = 3/14 = 0.2143
Allele Frequencies
p = Frequency of A = [(2 * 7) + 4] / 28 = 18/28 = 0.643
q = frequency of a = [(2*3)+ 4] / 28 = 10/28 = 0.357
GEN 2:
Genotype #s
AA = 9
Aa = 0
aa = 5
Total = 14
Genotype Frequencies
AA = 9/14 = 0.6429
Aa = 0/14 = 0
aa = 5/14 = 0.3571
Allele Frequencies
p = Frequency of A = [(2 * 9) + 0] / 28 = 18/28 = 0.643
q = frequency of a = [(2*5)+ 0] / 28 = 10/28 = 0.357
GEN 3:
Genotype #s
AA = 9
Aa = 0
aa = 5
Total = 14
Genotype Frequencies
AA = 9/14 = 0.6429
Aa = 0/14 = 0
aa = 5/14 = 0.3571
Allele Frequencies
p = Frequency of A = [(2 * 9) + 0] / 28 = 18/28 = 0.643
q = frequency of a = [(2*5)+ 0] / 28 = 10/28 = 0.357
GEN 4:
Genotype #s
AA = 9
Aa = 0
aa = 5
Total = 14
Genotype Frequencies
AA = 9/14 = 0.6429
Aa = 0/14 = 0
aa = 5/14 = 0.3571
Allele Frequencies
p = Frequency of A = [(2 * 9) + 0] / 28 = 18/28 = 0.643
q = frequency of a = [(2*5)+ 0] / 28 = 10/28 = 0.357
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