Directions: For the electron configuration Is2 is read as 1s2. Write your scient

Question

Directions: For the electron configuration Is2 is read as 1s2. Write your scientific notation with two decimal points. SPELLING COUNTS! -Given Values- Electron Configuration: = 1 s2.2s2.2p6.3s1 Ions: -Cu Distance (nm) 3.72 Compound 1: Sodium Selenide: Na2Se Molecular Formula = H2SiF6 Selected Element H Compound 2 CuO Compound 3 CH3COOH 1) How many atoms or molecules are there in a mole of a substance? 2) An element with the electron configuration shown above has how many electrons. 3) The ion on the the list below has an electron structure that is identical to which inert gas? (Spell Correctly) 4) The electrons that occupy the outermost filled shell are called 5) Calculate the force of attraction between a cation with a valence of +2 and an anion with a valence of -1, the centers of which are separated by a distance in nm shown above 6) Compute the percent ionic character of the interatomic bonds for Compound 1 found above 7) From the Molecular Formula given above, what is the percentage (by weight) of the selected element 8) For Compound 2, indicate the type of primary (interatomic) bonding (Ionic, Covalent, or Metallic) 9) For Compound 3, indicate the type of primary (interatomic) bonding (Ionic, Covalent, or Metallic): Your Answer Your Answer Your Answer Your Answer Your Answer Your Answer Your Answer Your Answer Your Answer

Explanation / Answer

1.One mole of any substance contains avagrado number or molecules=6.023*10^23

2.For the above electron configuration is for Na(sodium).from the Electron configuration count the numbers number of electrons in each orbit here 2+2+6+1 equals to 11.11 electrons.

3.Cu(copper) atomic number 29.near inert gases to Cu Is Argon(Ar).Cu also written as (Ar) 3d10 4s1.Cu doesnot have exact inergas configuration.

4.Outer most shell called as valence shell.And electron in the valence shell is called as valence electrons.

5.converting the ion charges into the units of coulomb by multiplying with 1.9*(10^-19).Then the cation charge is 2*1.9*(10^-19)=3.8*(10^-19).Anion charge=1*1.9*(10^-19)=1.9*(10^-19).Distance=3.72*(10^-9)Meters.(1nanometere=10^-9 meters) .

F=k*q1(charge in coloumb)*q2 (charge in coloumb)/d2(diameter).Where constant k=9*109

F=(9*109)*(3.8*(10^-19))*(1.9*(10^-19)) /(3.72*(10^-9)2==4.69*10-11 N.

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