Problem Statement: Consider a round beam of diameter d 25 mm, length L = 10 mm,

Question

Problem Statement: Consider a round beam of diameter d 25 mm, length L = 10 mm, cartievered (clamped) to the wall (as shown in the figure), loaded by P- 3.5 kN. Further pay attention to points A, B, and C (half way between A and B) in the cross section at the wall, where the bending moment is maximum Hint: The location of the centroid of half a circle can be found in Table A-18. Hint: The first moment of area for the shaded area in the figure isQ and the width of the base of that shaded area is b=2V(r2-y ),where y = 6.2500 mm is the distance from the center of the circle to the base of the shaded area and r is the radius of the circle Then, calculate: , at point A. Try at point A ·T,naz at point A at point B. Try at port B. Tmax at point B. o, at point c. ·Tx, at point c. ·T,nar at point C. Answer tolerances 2%. Be sure to include units and the correct sign with your answer. The sign of the bending moment M and the shear force V are determined by the sign convention

Explanation / Answer

a) Point A is at the top so Normal stress in X direction is given by 32 M/ ( d^3)

Where M = P × L

d= 25mm ,Substituting above we get maximum stress in X -direction = 22.81 N/mm^2

b) since point A is at top shear stress in XY plane will be zero,

c) for maximum shear stress at that point it will be (Sx - Sy)/2

Where Sx is normal stress in X direction and Sy normal stress in Y direction. Since Sy = 0

So maximum shear stress at point A= 22.81/2

= 11.405 N/mm^2

d) since Point B is at neutral fibre so no bending stress hence normal stress in X direction is zero .

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.