Magnetic Fied unit converter Meas Search Textbook solutions chegg com The two wi

Question

Magnetic Fied unit converter Meas Search Textbook solutions chegg com The two wires shown in the figure below are separated by d 8.9 cm and carry currents of I 4.50 A in opposite directions. (a) Find the magnitude and direction of the net magnetic field at a point midway between the wires. v HT magnitude 40.45 direction into the page (b) Find the magnitude and direction of the net magnetic field at point Pi, 8.9 cm to the right of the wire on the right. v HT magnitude 5.056 direction out of the page (c) Find the magnitude and direction of the net magnetic field at point Pr, 2d 17.8 cm to the left of the wire on the left. 11.44 Your response differs from the correct answer by more than 100%. magnitude direction out of the page

Explanation / Answer

(C) due to the left side wire,

B1 = u0 I / (2 pi (2d)) = u0 I / (4 pi d) out of page

now due to right side wire,

B2 = u0 I / (2 pi (3d)) = u0 I / ( 6 pi d) into the page

B_P2 = B1 - B2 = u0 I / (12 pi d) out of the page

= (4pi x 10^-7) ( 4.50 )/ (12 x pi x 0.089)

= 16.85 x 10^-6 T = 16.85 u T

Ans : 16.85 uT

out of the page

(b) due to circular loop.

B = u0 I / 2 R

2 pi R = L^2 = 0.380^2

2 R =0.046

B = (4pi x 10^-7 x 11.6) / (0.046)

B = 317.1 x 10^-4 T

= 317.1 uT

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