We are going to start out this lab by investigating how to calculate the moment
ID: 2075259 • Letter: W
Question
We are going to start out this lab by investigating how to calculate the moment of inertia. Let's start out by considering the barbell shown in Figure P-1. 'Moment of Inertia' is the measure of an object's resistance to rotational motion, also known as its 'rotational inertia'. Shown here are two barbells. They have the same mass but have different moments of inertia. Each is intended to be held in the center and twisted. The bars shown Figure P-1 have two different configurations. Use the in information given in the moment of inertia facts to determine an equation for the moment of inertia for each of the two configurations. Assuming that a person's hand is placed in the center twists bar. a) Masses Close: b) Masses Far: Which one would you expect to have a larger moment of inertia? The moment of inertia of the pipe rotated about its center of mass, I = 1/12 ML^2 M is the mass of the pipe and L is the overall length of the pipe. The moment of inertia of an object rotating about an exterior point is I = MR^2, M is the mass and R is the distance from the center of the object to the center of rotation. The moment of inertia of a system of objects is the sum of the moments of inertia of the objects that make up that system.Explanation / Answer
Trick: To calculate the total moment of inertia of more than one object about an axis, add up all the individual mass' moment of inertia about that point.
2.a) Masses Close: Total I = Imasses + Irod =( MR2+MR2 )+ 1/12 ML2 =2MR2 + 1/12 ML2
2.b) Masses Far: Total I = Imasses + Irod =[ M(L/2)2+M(L/2)2]+ 1/12 ML2 =2ML2 /4+ 1/12 ML2
(1/2 + 1/12) ML2 = 7/12 ML2
3. Masses far configuration will have the maximum moment of inertia. Since the distance from the mass to the point of rotation is more here and it's squared.
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