1.This problem is based on a patient standing on one limb. For the following set

Question

1.This problem is based on a patient standing on one limb. For the following set of scenarios, determine: i. The torque that the abductor muscles must provide in order to maintain the body position. ii. The abductor muscle force that was required to produce this torque iii. The magnitude of the net hip joint reaction force. The abductor muscles are assumed to absorb the entire adducting torque produced by the body weight on the hip joint of the stance leg. The following table and figure contain the relevant parameters. 0.05 m 0.10 m Weight of the Patient (minus 700 N stance leg) Moment arm of the abductor 0.05 m muscle force orientation of muscle relative to 700 Moment arm of the weight of the 0.10 m 700 N nus stance

Explanation / Answer

Torque of the body weight about the hip joint

                        = 700 *0.1 = 70 N-m

The muscle has to provide an equvel torque in opposite direction to keep the body in equilibrium

          torque required = 70 N-m

Fm makes 70 deg with the horizontal,

verticla component only contributes to the troque = Fm*Sin(70) arm of the torque = 0.05 m

Fm*Sin(70) *0.05 = 70 N-m

Fm = 1490 N

force acting at the hip joint

Fm*Sin(70) - vertically down

W = 700 N weight of the body, vertically down

Vertical reaction at the hip joint = 700 +1400 = 2100 N vertically upward

Horizontal reaction = Fm*Cos(70) = 510 N

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