Let\'s begin with a simple calculation of the weight of air using density. Find
ID: 2075654 • Letter: L
Question
Let's begin with a simple calculation of the weight of air using density. Find the mass of air and its weight in a living room that has a 3.5 m times 4.1 m floor and a ceiling 3 3 m high. What are the mass and weight of an equal volume of water? of air it contains. The room's volume is V = l times w times h = (3.5m)(4.1m)(3.3m) = 47.355m^3 Air has density of rho = 1.2 Kg/m^3. The mass of the air in the room is m = rho V = (1.2 kg/m^3)(47, 355m^3) = 56, 826kg The weight of the air is w = mg = (56 826kg)(9.8 m/s^2) = 556.9 N The density of water is rho = 1.0 times 10^3 kg/m^3. Thus, the mass of a volume of water that would fill the room is m = rho V = (1000 kg/m^3)(47.355m^3) = 47355 times 10^4 kg The weight is w = (4.7355 times 10^4 kg)(9.8 m/s^2) = 4641 times 10^5N The weight of the air is about 125 lb. Does it surprise you that a roomful of air weights this much? But the weight of the same volume of water is about 1.04 times 10^5 lb, or 52.2 tons! This much weight would certainly collapse the floor of an ordinary house. What volume of water would have a mass equal to the mass of air in the room? Express your answer in liters to two significant figures.Explanation / Answer
Mass of air=density of air*volume of air
Mass=3.5*4.1*3.3*1.2=56.826 kg
Weight=mass*9.8=556.89 N
If it was water,density =1000 kg/m(3)
Mass=3.3*4.1*3.5*1000=47355 kg
Weight=464079 N
Part A
Let the volume of water be V
V*1000=mass of air
V=0.056 cubic meter or in term of litre V=56 litre
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