Introduction: There has been an incident at one of the reactors of the Chernobyl
ID: 2075749 • Letter: I
Question
Introduction: There has been an incident at one of the reactors of the Chernobyl nuclear power plant. As the newest members of the engineering staff, are on duty tonight (the newest members always get night duty). So you must start planning the recovery operation. You have 30 minutes to complete your assigned calculations. Then you will have 5 minutes to share your results among your team. You will have minutes to present your results to your peers and direct management. A reactor operator at Chernobyl was standing in a gallery overlooking the reactor floor. He saw the reactor cap and 2000 fuel bundle covers (each weighing about 770 lbf) placed on top of the reactor cap begin to bounce up and down (but remain in place). He ran from his location to the control room. Using the following information, calculate how long it took him (sec) to alert the operators to the problem. Reactor floor: 35 m above ground level Gallery: 45 ft above the reactor floor Control room: 10 m above ground level Hallway from stairs to control room: 229 feet Assume he traveled 8 mph for the entire time. Assume that for every 7 inches of vertical travel (down the stairs) he traveled 10.5 horizontally. The reactor cap is a cylinder 49 ft in diameter and 8 ft thick. The material of the cap has a density of 66.3 lbm/ft^3. What was the total weight on the reactor top (US tons)? The last view we had of the reactor top showed the fuel bundle covers launching off the reactor cap. What is the minimum pressure (psi) needed to lift one fuel bundle cover (assume each fuel bundle cover is over a pipe that is 3 inches in diameter).Explanation / Answer
control room GF +10 m
reactor floor - GF +35 m
Gallery - RF + 45 ft
Gallery to Control room height descended = 25 m + 45 ft
= 25*3.28 + 45 = 127 ft - vertical descent
= 127 *10.5/7 ft - horizontal travel
= 190.5 ft
Hall way distance to control room = 229 ft
total distance = 229 + 190.5 = 419.5 ft
speed = 8 mph = 11.73 ft /s
time = 419.5 /11.7 = 35.75 s
b) reactor cap
diameter D = 49 ft
thickness h = 8 ft
density d = 66.3 lbm/cft
volume V = 3.14 *(49/2)2 *8 = 15086 cft
mass = 15086*66.3 = 1000197 lbm
= 500.096 US-tons ( 1 US ton = 2000 lbm
Fuel bundel weight = 770 lbf
area = 3" dia = 0.491 sq.ft
pressure = 770/0.491 = 1568 psi , required to lift one fuel bundel.
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