9) * A person of mass 80 kg is riding a bicycle of mass 15 kg. If the gauge pres
ID: 2075878 • Letter: 9
Question
9) * A person of mass 80 kg is riding a bicycle of mass 15 kg. If the gauge pressure in the each tire is 1.2x106 Pa, what is the area of contact between each tire and the ground? (Gauge pressure is the amount by which the pressure exceeds atmospheric pressure
9) * A person of mass 80 kg is riding a bicycle of mass 15 kg. If the gauge pressure in the each tire is 1.2x106 Pa, what is the area of contact between each tire and the ground? (Gauge pressure is the amount by which the pressure exceeds atmospheric pressure
9) * A person of mass 80 kg is riding a bicycle of mass 15 kg. If the gauge pressure in the each tire is 1.2x106 Pa, what is the area of contact between each tire and the ground? (Gauge pressure is the amount by which the pressure exceeds atmospheric pressure
Explanation / Answer
Force on each tire = mg/2 <---- as the whole weight needs to be divided equally between the two tires
Now, pressure on each tire , P = F/A = mg/(2A)
So, P = (1.013*10^5 + 1.2*10^6) = mg/2A
So, (1.013*10^5 + 1.2*10^6) = 15*9.8/(2*A)
So, A = 5.65*10^-5 m2 <---------answer
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