Problem 6.30 A space probe sends a containing 500 times 500 elements, each conta
ID: 2075969 • Letter: P
Question
Problem 6.30
Explanation / Answer
6.30] a] The most fundamental frequency will give the overall structure to the signal. It is the regular component of the signal with the shortest frequency. Here, this is the signal with time period 5 ms
so, the fundamental frequency is f = 1/T = 1/5ms = 200 Hzo = 1/To = 1/5ms = 200 Hz
b] The highest harmonic will be the regular component of the signal with the highest frequency.
Here, there are 4 small oscillations in 5 ms
so time for 1 oscillations is: 5ms/4 = 1.25 ms
=> f = 1/1.25ms = 800 Hz = 4(fo).
therefore, this frequency is the fourth harmonic (3rd overtone).
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