Help please explain in full details why it is the answer! Thank you so much!! 20

Question

Help please explain in full details why it is the answer! Thank you so much!! 2010 Quiz Ch 9 4/12/16 Name l. Water has a density of I000kg/m'. Mercury has a density of 13600 kg/m'. A full container of water has the same massas a full container of mercury. Which of the following is true? a. The container of mercury has a bigger volume b. The container of mercury has a smaller volume to the c. The container of water weighs more d. The container of mercury weighs more 2. In the picture of the U-tube, the left side is open to the air. The right side is closed, and the substances in the U-tube are labeled. Which horizontal line shows where the pressures are equal on each side of the tube? water 3. A block of Styrofoam and a block of gold are each 10 cm They are each held under water. When they are released, the Styrofoam rises to the surface and the gold sinks to the bottom. While they are still completely submerged underwater. a. the buoyant force on the styrofoam is less than the buoyant force on the gold b. the buoyant force on the styrofoam is equal to the buoyant force on the gold c, the buoyant force on the styrofoam is greater than the buoyant force on the gold 4. Water flows through a pipe of area A with speed of v. Later, the pipe changes its size and the speed is 4v. What is the cross-sectional area of the pipe atthis point? a. 2A b. A/2 c, 4A d. Ak4 5. If the speed of water in a pipe stays constant as it goes up a hill, where is the pressure the lowest? a. At the top of the hill b, at the bottom of the hill c. the pressure is the same everywhere

Explanation / Answer

1.

Answer is B.The container of mercury has smaller volume.

since Volume is given by

Volume=mass/density

Here volume is inversly proportional to density of liquid.therfore the container of mercury has smaller volume

4.

from continutiy equation

Q1=Q2

A1V1=A2V2

A2=A1*(V1/V2)=A*(V/4V)

A2=A/4

5.answer is A.at the top of the hill

from Bernoulli's equation

P1+(1/2)pV12+pgh1=P2+(1/2)pV22+pgh2

Here V1=V2

P1=P2+pg(h2-h1)

therefore pressure at the top of the hill is lowest

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