Some unpolarized light has an intensity of 1345 W/m^2 before passing through thr

Question

Some unpolarized light has an intensity of 1345 W/m^2 before passing through three polarizing filters. The transmission axis of the first filter is vertical. The second filter's transmission axis is 28.0 degree from vertical. The third filter's transmission axis is 42.0 degree from vertical. What is the intensity of the light that emerges from the three filters? W/m2 The magnetic field of an electromagnetic wave is given by B = 5.0 times 10^10 sin(kx = omega t) T. (a) If the wavelength is 814 nm, what are the frequency, angular frequency, and wave number of this wave? F = Hz omega = rad/s k = rad/m (b) What is the total energy density of this wave? J/m^3

Explanation / Answer

According to the law of malus

I = I0 cos2

The unpolarised light passing through the first vertical polarizer is =900

cos2 (900) = 0

Intensity of light after first polarizer I = I0 cos2 =0

Through the second polarizer =1520

cos2 (1520) = 0.1289

Intensity of light after second polarizer I = 173.37 W/m2

through the third polarizer =1380

cos2 (1380) = 0.9479

Intensity of light after third polarizer I = 164.34 W/m2

Frequency, f= c/ ; c=3x108 m/s

       f= 3.6855 Mhz

wave number, k= 2/ = 7.718x106

angular frequency, = 2f

                                     = 23.1567x106 rad/sec

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