In a physics laboratory experiment, a coil with 180 turns enclosing an area of 1
ID: 2076174 • Letter: I
Question
In a physics laboratory experiment, a coil with 180 turns enclosing an area of 11.7 cm^2 is rotated during the time interval 3.20 times 10^-2 s from a position in which its plane is perpendicular to Earth's magnetic field to one in which its plane parallel to the field. The magnitude of is Earth's magnetic field at the lab location is 5.50 times 10^-5 T. What is the total magnitude of the magnetic flux (phi_initial) through the coil before it is rotated? 1.16 times 10^-5 wb 3.71 times 10^-7 Wb 6.44 times 10^-8 Wb 2.06 times 10^-9wb 0 wbExplanation / Answer
N = 180
A = 11.7 cm^2 = 11.7*10^-4 m2
t = 3.2*10^-2 s
B = 5.5*10^-5 T
Magnetic flux = N*B*A = 180*5.5*10^-5*11.7*10^-4
= 1.16*10^-5 Wb <------ option A
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.