A 0.100 kg mass is attached to a string 75 cm long and swings in a horizontal ci
ID: 2076606 • Letter: A
Question
A 0.100 kg mass is attached to a string 75 cm long and swings in a horizontal circle, revolving once every 0 80 s. Calculate: a) the centripetal acceleration of the mass. b) the tension in the string. A 0.50 kg mass is attached to a string 10 m long and moves in a horizontal circle completing 1 revolutions in 0 5 seconds. Calculate: a) the centripetal acceleration of the mass. b) the tension in the siring. It takes a 900 kg racing car 12 3 s to travel at a uniform speed around a circular racetrack of radius 90.0 m. What is the centripetal force acting on the car, and which force provides it? A 2.0 kg object is tied to the end of a cord and whirled in a horizontal circle of radius 4.0 m completing 2 revolutions in 6 seconds Determine: a) the velocity of the object. b) the acceleration of the object. c) the pull of the object. d) what happens if the cord breaks. A steel beam is rotated in a horizontal plane to provide the centripetal acceleration for training pilots. If the pilot sits 2.0 m from the center of rotation, at what speed must he rotate to experience a horizontal centripetal acceleration of 78 m/s^2 ?Explanation / Answer
Here ,
6)
m = 0.10 Kg
L = 75 cm = 0.75 m
T = 0.80 s
angular velocity w = 2pi/T
w = 2pi/.80
w = 7.85 rad/s
a) centripetal acceleration = w^2 * L
centripetal acceleration = 7.85^2 * 0.75
centripetal acceleration = 46.25 m/s^2
b)
tension in the string = m * a
tension in the string = 0.100 * 46.25
tension in the string = 4.62 N
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