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[15]2. A concave spherical mirror has a radius of curvature of 45.9 cm. Choose t

ID: 2076769 • Letter: #

Question

[15]2.   A concave spherical mirror has a radius of curvature of 45.9 cm. Choose the answer below that best describes the image that is formed by an object that is located 15.4 cm in front of the mirror.
Answer: (a) Real, inverted, magnified 0.22 times, and is 9.30 cm in front of the mirror.   (b) Virtual, erect, magnified 7.04 times,
and is 108.4 cm behind the mirror.    (c) Virtual, erect, magnified 2.23 times, and is 34.3 cm behind the mirror.   (d) Virtual, erect, magnified 3.04 times, and is 46.8 cm behind the mirror.   (e) Real, inverted, magnified 0.22 times, and is 9.30 cm in front of the
mirror.

[15]10. A convex spherical mirror has a radius of curvature of 9.8 cm. Choose the answer below that best describes the image that is formed by an object that is placed 26.4 cm in front of the mirror.
Answer: (a) Virtual, upright, magnified 0.15 times, and is 3.32 cm behind the mirror.    (b) Real, inverted, magnified 0.65 times, and is 1.18 cm in front of the mirror.   (c) Virtual, upright, magnified 0.18 times, and is 4.42 cm behind the mirror. (d) Real, inverted, magnisfied 0.88 times, and is 2.42 cm in front of the mirror.          (e) Virtual, upright, magnified 0.16 times, and is 4.13 cm behind the mirror

Explanation / Answer

2. f = R/2 = 22.95 cm

object distance, p = 15.4 cm

1/f =1/p + 1/q

q = - 46.8 cm

q < 0 , hence image is virtual and behind the mirror.

m = - q / p = - (-46.8)/ 15.4 = 3.04

m > 0 hence image is erect.

|m| > 1 , image is enlarged.


ans(d)

10. f = - R/2 = - 4.9 cm

p =26.4 cm

1/f =1/p + 1/q

q = - 4.13 cm

virtual, upright

m = 4.13 / 26.4 = 0.16

Ans(e)

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