I have a couple answers to this problem but I can\'t seem to figure out C and E.

Question

I have a couple answers to this problem but I can't seem to figure out C and E.

A cannon tilted upward at = 31.1 fires a cannonball with a speed of 87.0 m/s on level ground.

A) At the instant the cannonball is fired, what is the component of the cannonball’s velocity parallel to the ground? 74.5 m/s

B) At the instant the cannonball is fired, what is the component of the cannonball’s velocity perpendicular to the ground? 44.9 m/s

C) What is the maximum height reached by the cannonball (above the ground)?

D) At what time after being fired does the cannonball reach it's maximum height above the ground? 4.58 seconds

E) What is the distance that the cannonball travels horizontally before reaching the ground again (assuming it was shot at exactly ground level with the velocity given)?

Explanation / Answer

here,

theta = 31.1 degree

initial speed , u = 87 m/s

C)

the maximum height reached , hmax = (uy)^2 /(2 * g)

hmax = ( 87 * sin(31.1))^2 /( 2 * 9.8) m

hmax = 103.3 m

D)

the time after which the cannon ball reached maximum height , t = uy /g

t = 87 * sin(31.1) /9.81 s

t = 4.58 s

E)

thyen distance travelled by the canon ball horizontally before reaching the ground again , x = u * cos(theta) * t

x = 87 * cos(31.1) * 4.58 m

x = 341.2 m

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